Grcko wrote: I haven't gotten to the turn signals yet but I did get an led flasher that someone here used on a KZ440 and it worked for them,
Yes it is the dashboard light. I am sure you can fool it with one of the two ideas I asked about. It makes the sensor think more power is being used than what the LED actually uses. I am just not sure which one it is or if both: which one is the best fix. If neither work, I guess I will have to get creative .
The brake light flashing issue is not exactly the same problem as the turn-signal flasher issue.
Regular light bulbs act like a short when very little voltage is applied to them (similar to when you read their resistance with a meter). It's only when they get enough voltage/power that the filament gets super-hot and the resistance of the bulb increases. The brake light flasher applies a tiny bit of voltage/power to the bulb, but not enough to heat up the filament. As long as the filament is in tact, that little bit of power gets shorted to ground by the filament. That is what the brake light flasher is trying to detect.
LED's sort of act in the opposite way to filaments. When you apply a tiny bit of voltage/power, the resistance is very high. Then when you apply more voltage/power, suddenly the resistance drops.
That opposite reaction means it will take a drastic amount of compensation with a resistor. The resistor will have to be big in order to dissipate the type of energy that will be required. A bulb dissipates energy as light and heat, but a resistor dissipates only heat, so it will be hot and will need to be big to not burn up.
The requirement of the filament to act as a short means that in order to replicate that with a resistor, you will have to use a very low resistance resistor. But, when 12v gets applied while hitting the brakes, a very large amount of power will need to be dissipated. A bulb would increase its resistance to reduce the power requirement, but a resistor does not change. This makes the resistor's size (wattage) requirement impractically large physically.
Here is an initial rough estimate.
When off, an 1157 bulb's filament acts something like a 1 ohm resistor. With little voltage applied, the wattage is very tiny.
When on, an 1157 bulb's filament acts something like a 6 ohm resistor. Dissipating somewhere around 25 watts. (12.8v @ 2.1 amps).
In order to replicate the filament for the brake flasher, when the brakes are not applied, you might need a resistor that is around 1 ohm. Resistance of a resistor does not change much under normal conditions, so that same resistor will have to dissipate a lot of power when the brakes get applied. Let's see how much.
Let's assume the system is running at 12.8 volts. The resistor is 1 ohm. That means there will be 12.8 amps flowing. First of all notice that the 10 amps of the lighting fuse will blow. But then also notice if we multiply volts times amps to get the wattage, we need a 163 watt resistor. To be safe, you will want to upgrade that to a 200 watt resistor.
Now take a look on the internet to see how big a 200 watt resistor is. You can use that to cook hot dogs on.
But this is to replicate the resistance of an 1157 bulb. Perhaps making the flasher work won't take such drastic measures, but an 1157 bulb is what it was intended to detect, so that is the starting point.
The next step would be to apply power to the flasher and determine exactly how small the resistance needs to be in order to make it stop flashing.
Now realize, all of that is very different from the turn signal flasher problem. The brake flasher problem is about how the bulb reacts when it's "off". The turn signal flasher problem is about how much current/power the bulb uses when it is "on". That is much more manageable problem with a simple electronic flasher.
By the way, the most complicated suggestion I gave earlier is about the same difficulty as adding a resistor or diode, but is easier to get, and only a bit bigger than the original brake flasher unit. You can get this relay at any autoparts store.